Question

find the greatest 4 digit number which is exactly divisible by each 8,12 and 20

Answer 1

Answer:

Hey mate there is your answer

Step-by-step explanation:

27 = 3^3

18 = 2 * 3^2

12 = 2^2 * 3

15 = 3 * 5

Lcm = 2^2 * 3^3 * 5

= 540

Largest 4 digit is 9999

9999/540 = 279 remainder

so 9999-279 = 9720

Answer 2

Answer:

Step-by-step explanation:

27=3^3

18=2*3^2

12=2^2*3

15=3*5

Lcm=2^2*3^3*5=540

Largest 4 digit no. 9999

9999/540=279

9999-279=9720

Mark me as brainliest