Question

Find the greatest 4 digit number which is exactly divisible by 20 48 and 45

Answer 1

Step-by-step explanation:

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The greatest 4-digit number is 9999.

The greatest 4-digit number is 9999.Now, Find the LCM of 40, 48 and 60.

The greatest 4-digit number is 9999.Now, Find the LCM of 40, 48 and 60.40=2\times 2\times 5

The greatest 4-digit number is 9999.Now, Find the LCM of 40, 48 and 60.40=2\times 2\times 548=2\times 2\times2\times 2\times 3

The greatest 4-digit number is 9999.Now, Find the LCM of 40, 48 and 60.40=2\times 2\times 548=2\times 2\times2\times 2\times 360=2\times 2\times 3\times 5

The greatest 4-digit number is 9999.Now, Find the LCM of 40, 48 and 60.40=2\times 2\times 548=2\times 2\times2\times 2\times 360=2\times 2\times 3\times 5LCM(40,48,60)=2\times 2

The greatest 4-digit number is 9999.Now, Find the LCM of 40, 48 and 60.40=2\times 2\times 548=2\times 2\times2\times 2\times 360=2\times 2\times 3\times 5LCM(40,48,60)=2\times 2LCM(40,48,60)=4

The greatest 4-digit number is 9999.Now, Find the LCM of 40, 48 and 60.40=2\times 2\times 548=2\times 2\times2\times 2\times 360=2\times 2\times 3\times 5LCM(40,48,60)=2\times 2LCM(40,48,60)=4Divide 9999 by 4 so that we get the remainder,

The greatest 4-digit number is 9999.Now, Find the LCM of 40, 48 and 60.40=2\times 2\times 548=2\times 2\times2\times 2\times 360=2\times 2\times 3\times 5LCM(40,48,60)=2\times 2LCM(40,48,60)=4Divide 9999 by 4 so that we get the remainder,9999 = 2499\times4 + 3

The greatest 4-digit number is 9999.Now, Find the LCM of 40, 48 and 60.40=2\times 2\times 548=2\times 2\times2\times 2\times 360=2\times 2\times 3\times 5LCM(40,48,60)=2\times 2LCM(40,48,60)=4Divide 9999 by 4 so that we get the remainder,9999 = 2499\times4 + 3Remainder is 3.

The greatest 4-digit number is 9999.Now, Find the LCM of 40, 48 and 60.40=2\times 2\times 548=2\times 2\times2\times 2\times 360=2\times 2\times 3\times 5LCM(40,48,60)=2\times 2LCM(40,48,60)=4Divide 9999 by 4 so that we get the remainder,9999 = 2499\times4 + 3Remainder is 3.Now, Subtract the remainder from 9999.

The greatest 4-digit number is 9999.Now, Find the LCM of 40, 48 and 60.40=2\times 2\times 548=2\times 2\times2\times 2\times 360=2\times 2\times 3\times 5LCM(40,48,60)=2\times 2LCM(40,48,60)=4Divide 9999 by 4 so that we get the remainder,9999 = 2499\times4 + 3Remainder is 3.Now, Subtract the remainder from 9999.9999-3=9996

The greatest 4-digit number is 9999.Now, Find the LCM of 40, 48 and 60.40=2\times 2\times 548=2\times 2\times2\times 2\times 360=2\times 2\times 3\times 5LCM(40,48,60)=2\times 2LCM(40,48,60)=4Divide 9999 by 4 so that we get the remainder,9999 = 2499\times4 + 3Remainder is 3.Now, Subtract the remainder from 9999.9999-3=9996Therefore, The required number is 9996 which is exactly divisible by 40, 48 and 60.

Answer 2

Answer:

1440

Step-by-step explanation:

The LCM of 20, 48 and 45 is 720

If we multiply 720 with 2, we will get 1440

So, 1440 is the smallest 4 digit number which can be exactly divided by 20 48 45.

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