Find the greatest 4-digit number which is exactly divisible by 12, 18, 21 and 28.
Answers
The number that I came up with was 9,072. I found the LCM (Least Common Multiple) using Prime factorization which was 1,008 but you wanted the highest 4 digit number so I multiplied 1,008 to the highest whole number that would still render a 4 digit answer, which was 9 (1,008 * 9 = 9,072).
12 = 2 x 2 x 3
16 = 2 x 2 x 2 x 2
24= 2 x 2 x 2 x 3
28 = 2 x 2 x 7
36 = 2 x 2 x 3 x 3
LCM = 2 x 2 x 2 x 2 x 3 x 3 x 7 = 1,008
1,008 x 9 = 9,072
9,072 is divisible by 12(756), 16 (567), 24 (378), 28 (324), & 36(252)
I hope that helps!
Plz mark my answer as brainliest.
Answer:
Hello There,
This is your answer.
Step-by-step explanation:
The greatest 4 digits number is 9999
The LCM of 12, 18, 21, 28 is 252
On dividing 9999 by 252 the remainder comes out to 171
Required number = 9999 - 171 = 9828
Your answer is 9828.
