Math, asked by trishatanwar, 1 year ago

find the greatest 4 digit number which is exactly divisible by 20, 28 and 45

Answers

Answered by ishwarsinghdhaliwal
21
LCM of 20,28 & 45
20= 2×2×5
28= 2×2×7
45=3×3×5
LCM= 2××2×3×3×5×7=1260
Greatest 4 digit number is 9999
Now divide 9999 by 1260 we will get remainder 1179
9999 – 1179 = 8820
8820 is the greatest number 4-digit number divisible by 20,28 and 45
Answered by titardotitar
7

Answer:

Step-by-step explanation:

LCM of 20,28 & 45

20= 2×2×5

28= 2×2×7

45=3×3×5

LCM= 2××2×3×3×5×7=1260

Greatest 4 digit number is 9999

Now divide 9999 by 1260 we will get remainder 1179

9999 – 1179 = 8820

8820 is the greatest number 4-digit number divisible by 20,28 and 45

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