find the greatest 4 digit number which is exactly divisible by 20, 28 and 45
Answers
Answered by
21
LCM of 20,28 & 45
20= 2×2×5
28= 2×2×7
45=3×3×5
LCM= 2××2×3×3×5×7=1260
Greatest 4 digit number is 9999
Now divide 9999 by 1260 we will get remainder 1179
9999 – 1179 = 8820
8820 is the greatest number 4-digit number divisible by 20,28 and 45
20= 2×2×5
28= 2×2×7
45=3×3×5
LCM= 2××2×3×3×5×7=1260
Greatest 4 digit number is 9999
Now divide 9999 by 1260 we will get remainder 1179
9999 – 1179 = 8820
8820 is the greatest number 4-digit number divisible by 20,28 and 45
Answered by
7
Answer:
Step-by-step explanation:
LCM of 20,28 & 45
20= 2×2×5
28= 2×2×7
45=3×3×5
LCM= 2××2×3×3×5×7=1260
Greatest 4 digit number is 9999
Now divide 9999 by 1260 we will get remainder 1179
9999 – 1179 = 8820
8820 is the greatest number 4-digit number divisible by 20,28 and 45
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