Math, asked by harshpatel206317, 1 month ago

Find the greatest 4-digit number which is exactly divisible by each of 12, 18 and 30. (3)​

Answers

Answered by ashvithareddy21
1

Answer:

960

Step-by-step explanation:

calculate the L.C.M 8, 10 and 12

L.C.M of 8, 10, 12 = 2 x 2 x 2 x 3 x 5

Hence, LCM of 8, 10, 12 = 120

We have to find the greatest 3 digit multiple of 120

Therefore, the number is 120 x 8 = 960

120 x 10 = 1200

120 x 12 = 1440

The 1200 and 1440 are not 3-digit numbers.

Hence, the greatest 3- digit number exactly divisible by 8, 10 & 12 is 960.

thank you..

Answered by vanshika4017
0

Answer:

We will get 9720. This number is the greatest 4 digit number exactly divisible by 8,12,18 and 30.

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