Find the greatest 4-digit number which is exactly divisible by each of 12, 18 and 30. (3)
Answers
Answered by
1
Answer:
960
Step-by-step explanation:
calculate the L.C.M 8, 10 and 12
L.C.M of 8, 10, 12 = 2 x 2 x 2 x 3 x 5
Hence, LCM of 8, 10, 12 = 120
We have to find the greatest 3 digit multiple of 120
Therefore, the number is 120 x 8 = 960
120 x 10 = 1200
120 x 12 = 1440
The 1200 and 1440 are not 3-digit numbers.
Hence, the greatest 3- digit number exactly divisible by 8, 10 & 12 is 960.
thank you..
Answered by
0
Answer:
We will get 9720. This number is the greatest 4 digit number exactly divisible by 8,12,18 and 30.
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