find the greatest 4-digit number which is exactly divisible by each of 8,12 and20
Answers
Answer:
9720
Step-by-step explanation:
Here it is asking for greatest four digits number divisible by 8,12,18 and 20.
Let first find out the LCM of 8, 12 ,18 and 30.
8 = 2³
12 = 2² * 3
18 = 2 * 3²
30 = 2 * 3 * 5
Therefore, L.C.M. is 2³ * 3² * 5 = 8 * 9 * 5 = 360.
Now you can say that the greatest four digit numbet divisible by 360.
The greatest four digit number is 9999. Now dividing it by 360 we get : (See the attachment.)
You get 279 as remainder and when you subtract it from the greatest four digit number(dividend) 9999 you'll get your answer as 9720.
So your final answer is 9720.
Hope it helps....
God bless. you !!!
Answer: 9720
Step-by-step explanation:
Here it is asking for greatest four digits number divisible by 8,12,18 and 20.
Let first find out the LCM of 8, 12 ,18 and 30.
8 = 2³
12 = 2² * 3
18 = 2 * 3²
30 = 2 * 3 * 5
Therefore, L.C.M. is 2³ * 3² * 5 = 8 * 9 * 5 = 360.
Now you can say that the greatest four digit numbet divisible by 360.
The greatest four digit number is 9999. Now dividing it by 360 we get : (See the attachment.)
You get 279 as remainder and when you subtract it from the greatest four digit number(dividend) 9999 you'll get your answer as 9720.