Question

find the greatest 4 digit number which on being divided by 6 12 18 24 and 30 leaves remainder 4 in each case ​

Answer 1

The greatest 4 digit number is 9999.

Frist find the L.C.M. of 6,12,18,24 and 30.

L.C.M. of 6,12,18,24 and 30 is 360.

Now,9999/360=27.

Remainder will be 279.

The required number=(9999-279)

=9720.