Math, asked by akhileshkumar1441985, 1 year ago

find the greatest 4 digit number which when divided by 36,30,24and 16 leaves a remainder 13 in each case​

Answers

Answered by Irfan1729
3

Answer:

Step 1: Know the greatest 4 digit number which is 9999

Step 2: Find the LCM of the given numbers which 36, 30, 24 and 16

i.e The LCM of given numbers is 720

Step 3: Divide the greatest 4 digit number by 720 and find the remainder

           

          720 ) 9999 (13

                 - 720

           ------------------

                   2799

                 - 2160

           ------------------

                     639

           ------------------

Step 4: Subtract the remainder from the greatest 4 digit number (or) multiply 720 and the quotient.

Note: You can do any one of these because the answer is same.

We get 9360 after subtraction or multiplication. 9360 is the greatest 4 digit number which perfectly divisible with 30, 36, 24 and 16.

Step 5: Add 13 to the number which came after step 4.

i.e 13+9360= 9373

The answer is 9373

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