Question

Find the greatest 4 digit number which when divided by 36 30 24 16 leaves a remainder 13 in each case

Answer 1

Step 1: Know the greatest 4 digit number which is 9999
Step 2: Find the LCM of the given numbers which 36, 30, 24 and 16
i.e The LCM of given numbers is 720
Step 3: Divide the greatest 4 digit number by 720 and find the remainder
           
          720 ) 9999 (13
                 - 720
           ------------------
                   2799
                 - 2160
           ------------------
                     639
           ------------------

Step 4: Subtract the remainder from the greatest 4 digit number (or) multiply 720 and the quotient.
Note: You can do any one of these because the answer is same.
We get 9360 after subtraction or multiplication. 9360 is the greatest 4 digit number which perfectly divisible with 30, 36, 24 and 16.
Step 5: Add 13 to the number which came after step 4.
i.e 13+9360= 9373
The answer is 9373
Hope it helps.

Answer 2

Answer:

9373

Step-by-step explanation:

9373 is the greatest 4 digit number which gives 13 in remaimder which when divided by 36,30,24,16