find the greatest 4 digit number which when divided by 36, 30, 24 and 16 leaves a remainder 13 in each case.
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Answer:
LCM(20, 24, 45)=8×9×5=360
20 24 45 | 2
10 12 45 | 2
5 6 45 | 2
5 3 45 | 3
5 1 15 | 3
5 1 5 | 5
1 1 1
9999/360=(9999/3)/120=(3333/3)/40=1111/40=27
360×27=7200+2520=9720
9720+11=9731
Step-by-step explanation:
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