Math, asked by kkaran4325, 2 months ago






Find the greatest 4-digit number which when divided by 36, 30, 24 and 16
leaves a remainder 13 in each case.

Answers

Answered by unique327
1

The LCM of 20,24 and 45 is 360.

The greatest four-digit number =9999.

Divide 9999 by 360. The remainder is 279.

The greatest four-digit number divisible by 360 is 9999−279=9720.

Now, the greatest four-digit number divisible by 360 and leaving a remainder 11 is 9720+11=9731.

Pls brainliest

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