Find the greatest 4-digit number which when divided by 36, 30, 24 and 16
leaves a remainder 13 in each case.
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The LCM of 20,24 and 45 is 360.
The greatest four-digit number =9999.
Divide 9999 by 360. The remainder is 279.
The greatest four-digit number divisible by 360 is 9999−279=9720.
Now, the greatest four-digit number divisible by 360 and leaving a remainder 11 is 9720+11=9731.
Pls brainliest
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