Find the greatest 4 digit number which when divided by 5 and 9 gives reminder 3 and 8 respectively
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28-May-2018 · 9 answers
You find the LCM of 3, 5, 7 and 9, which is 315. Then you find the largest multiple of 315 such that it's 9999 or less. This is 31.
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Since on dividing by 3 the remainder is 1, the sum of digits of the number must add upto a number, dividing which by 3 we get remainder 1
Since on dividing by 5 remainder is 3, unit place digit has to be either 3 or 8
Since on dividing by 9 remainder is 7, sum of digits should give remainder 7 when divided by 9
Only options (A), (B) satisfy these criteria
Since (A) is bigger, we divide it by 7 and find remainder which turns out to
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