Question

find the greatest 4 digits number when divided by 10,11,15 and 22 leaves 3,4,8 and 15 as remainders respectively
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Answer 1

9893

Step-by-step explanation:

10–3=7, 11–4=7, 15–8=7, 22–15=7

10=5×2,

11=11×1

15=3×5

22=2×11

LCM of 10,11,15,22=5×2×11×3 =330

Greatest 4 digit number 9999

9999÷330=30 with remainder 99

Greatest 4 digit number divisible by 330 is (9999–99)=9900

Our required number =9900–7 =9893 ans