find the greatest 5 digit number which is exactly divisible by 15 ,12,25.
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Answered by
3
hey !!
To find the largest number, first lets find the LCM of 15, 12 and 25.
We can see that the LCM is 300.
Now, we have to find the largest 5 digit multiple of 300.
we know that 300 * 330 = 99000
300 * 333 = 99900
This is the highest 5 digit multiple of 300.
Therefore, this is the largest 5 digit number exactly divisible by 15, 12 and 25.
To find the largest number, first lets find the LCM of 15, 12 and 25.
We can see that the LCM is 300.
Now, we have to find the largest 5 digit multiple of 300.
we know that 300 * 330 = 99000
300 * 333 = 99900
This is the highest 5 digit multiple of 300.
Therefore, this is the largest 5 digit number exactly divisible by 15, 12 and 25.
Answered by
2
That number will be the multiple of the LCM of 12,15 and 25
12 = 2*2*3
15= 3*5
25 = 5*5
LCM of 12,15 and 25
= 2*2*3*5*5
= 300
Lowest 6 digit number
= 1,00,000
(1,00,000)/300 = 333.33
So, Highest 5 digit number which will be divisible by 12,15 and 25
= 300x333
=9,99,000
12 = 2*2*3
15= 3*5
25 = 5*5
LCM of 12,15 and 25
= 2*2*3*5*5
= 300
Lowest 6 digit number
= 1,00,000
(1,00,000)/300 = 333.33
So, Highest 5 digit number which will be divisible by 12,15 and 25
= 300x333
=9,99,000
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