Question

Find the greatest 5-digit number which on dividing by 5, 10, 15, 20 and 25 leaves the remainder 4 in each case.
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Answer 1

Answer:

Any number that leaves a remainder of four when divided by a number x can be expressed as x * n + 4. When you want the same results with two or more divisors, you need to find the least common multiple of those divisors, lcm, and look for numbers that satisfy lcm * n + 4.

The lcm of (5, 10, 15, 20, 25) can be found by seeing those numbers as 5 * 1, 2, 3, 4, and 5. The lcm of (1, 2, 3, 4, 5) is 5 * 4 * 3 because 2 is already a factor of 4. So the lcm we need is 5 * 5 * 4 * 3 = 300.

That means we want the greatest 5-digit number expressable as 300 * n + 4. If we divide 99999 by 300, we get 333.33, so our number will be 333 * 300 + 4 = 99904.

Answer 2

Step-by-step explanation:

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