Find the greatest 5-digit number which on dividing by 5,10,15,20 and 25 leaves a remainder 4 in each case.
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Any number that leaves a remainder of four when divided by a number x can be expressed as x * n + 4. When you want the same results with two or more divisors, you need to find the least common multiple of those divisors, lcm, and look for numbers that satisfy lcm * n + 4.
The lcm of (5, 10, 15, 20, 25) can be found by seeing those numbers as 5 * 1, 2, 3, 4, and 5. The lcm of (1, 2, 3, 4, 5) is 5 * 4 * 3 because 2 is already a factor of 4. So the lcm we need is 5 * 5 * 4 * 3 = 300.
That means we want the greates 5-digit number expressable as 300 * n + 4. If we divide 99999 by 300, we get 333.33, so our number will be 333 * 300 + 4 = 99904.
The lcm of (5, 10, 15, 20, 25) can be found by seeing those numbers as 5 * 1, 2, 3, 4, and 5. The lcm of (1, 2, 3, 4, 5) is 5 * 4 * 3 because 2 is already a factor of 4. So the lcm we need is 5 * 5 * 4 * 3 = 300.
That means we want the greates 5-digit number expressable as 300 * n + 4. If we divide 99999 by 300, we get 333.33, so our number will be 333 * 300 + 4 = 99904.
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Answer:
Step-by-step explanation:
Find the LCM of 5 10 15 20 25 and LCM is 300 now find the greatest 5 digit number which is 99999 and divide the greatest five digit number by three hundred and answer will be 33 3.33 now the and after which is 33 3.33 multiply it by 300 and whatever will be the answer add it by 4 and we will be getting 99904.
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