Math, asked by yuganshgupta, 1 year ago

find the greatest 5 digit number which when divided by 3, 5, 8, and 12 and will have 2 as a remainder

Answers

Answered by inhumandrowsey

3 - 2 = 1

5 - 2 = 3

8 - 2 = 6

12 - 2 = 10

Taking the LCM of 1,3,6,10 = 30

greatest 5 digit number is 99999

so 99999/30 we are left with remainder 9

99999 - 9 = 99990

So greatest 5 digit number divisible by 30 is 99990

and 99992 is the number when divided by 3,5,8,12 will always leave remainder 2

inhumandrowsey: oh didnt see your comments, was busy solving questions and my exams are around the corner so studying :) takecare

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Answered by chaurasiavikas2014

Hey Friends,
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3-2=1
5-2=3
8-2=6
12-2=10

Take LCM of 1,3,6&10 is 30

Largest 5 digit no. is 99,999

So, 99,999÷30 =3333 9/30
The remainder is 9

Then, 99,999-9=99,990

Largest 5 digit no. which is divisible by 3,5,8&12 is 99,990

Hope it's help you!!!

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