Question

find the greatest 5 digits number which leaves q remainder of 7 when divided by 18,24 and 36​

Answer 1

Answer:

99798

Step-by-step explanation:

LCM of (8,14,18,24,48) = 1008

Find the multiple of 1008 closer the maximum 5 digit number, which is 99999

=> 99999 mod 1008 = 207

The largest 5 digit number divisible by 1008 = 99999 - 207 = 99792

Add 6 to this number => Required number is 99792 + 6 = 99798

This number would leave the reminder as 6 when divided by 8, 14, 18, 24, 48

Ans: 99798