Question

Find the greatest 6 digit no. Divisible by 28,49,63 and 70

Answer 1

Answer:

Solution:

prime factors of 28,49,63 and 70

= 28 = 2 * 7

= 49= 7

= 63 = 3 * 7

= 70 = 2 * 5 * 7

LCM = 2* 7* 3* 5* = 8820

Now we, know that,

greatest 6-digit number = 999999

so,

= Dividing greatest 6-digit number by LCM we get,

• 999999 ÷ 8820
• Quentient = 113

Remainder = 3339

therefore,

Required number = greatest 6-digit

number- remainder = 999999 - 3339

996660 (Ans)

Answer 2

Answer:

996660

Step-by-step explanation:

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