Question

find the greatest 6 digit number exactly divisible by 18,24,36

Answer 1

LCM OF 18,24,36= 72
NOW DIVIDE 999999 BY 72
AND SUBTRACT 999999 BY REMAINDER
999999- 63= 999936

Answer 2

LCM of 18,24 and 36

18 = 2 × $\bf\huge3^{2}$

24 = $\bf\huge2^{3}$ × 3

36 = $\bf\huge2^{2}$ ×  $3^{2}$

LCM (18,24,36) =  $\bf\huge2^{3}$ $\bf\huge3^{2}$

= 72

Largest 6 digit number is 999999

Now divide 999999 by 72

You will get 63 as remainder

Required Number = 999999 – 63  

= 999936