Math, asked by answer8854, 1 year ago

Find the greatest 6 digit number exactly divisible by 281

Answers

Answered by tejaskumar574
15
the greatest 6-digit no.=999999
99999/281
remainder=201
required no.=999999-201=999798
Answered by pinquancaro
17

Answer:

The greatest 6 digit number exactly divisible by 281 is 999798.      

Step-by-step explanation:

Given : The greatest 6 digit number exactly divisible by 281?

To find : The number?

Solution :

The greatest 6 digit number is - 999999

Now, to find number which is divisible by 281 we divide the greatest number by 281 and find the remainder then subtract the remainder from the dividend we get the required number.

Divide 999999 ÷ 281

Refer the attached figure for calculation,

Remainder is 201.

So, The required number is 999999-201=999798

Therefore, The greatest 6 digit number exactly divisible by 281 is 999798.

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