Math, asked by Amrita1010, 1 year ago

Find the greatest 6 - digit number of which is exactly divisible by 281.

Answers

Answered by pornimv
0
Greatest 6 digit number = 999999

281 ) 999999 (3558
843
_________
1569
1405
________
1649
1405
_______
2449
2248
________
201


Therefore ,

The remainder = 201

Now the greatest 6 digit number

which is exactly divisible by 281

= greatest 6 digit number - remainder

= 999999 - 201

= 999798
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