Math, asked by gpbeer27, 1 year ago

Find the greatest 6 digit number which is exactly divisible by 281.

Answers

Answered by Palak230
7
Greatest 6 digit number = 999999
For obtaining greatest 6 digit number which is exactly divisible by 281, let us divide 999999 by 281 :
Thus, the greatest 6 digit number divisible by 281 = (999999 – 201) = 999798. Here remainder is subtracted from largest 6 digit number.

Hope it helps.....
Answered by khusshimittal22
7
the answer is 999798
as we know greatest 6 digit no. is 999999
so dvide it by 281
281 ) 999999 ( 3558
843
_______
1569
1405
______
1649
1405
______
2249
2248
________
201
remainder = 201
999999-201= 999798
i hope it will help you
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