find the greatest 6 - digit number which is exactly divisible by 281.
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Answered by
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We know that ,
Greatest 6 digit number = 999999
281 ) 999999 (3558
843
_________
1569
1405
________
1649
1405
_______
2449
2248
________
201
Therefore ,
The remainder = 201
Now the greatest 6 digit number
which is exactly divisible by 281
= greatest 6 digit number - remainder
= 999999 - 201
= 999798
I hope this helps you.
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