Question

Find the greatest and the least 5 digit number that is exactly divisible by 115

Answer 1

Answer:

Greatest = 99935

Smallest = 10005

Step-by-step explanation:

99999 on dividing by 115 leaves remainder 64.

So, greatest 5 digit number is 99935 exactly divisible by 115.

10000 on dividing by 115 leaves remainder 110.

So, subtract 110 from 115 = 5.

Add 5 to 10000 = 10005. This is smallest 5 digit number which is exactly divisible by 115.

Answer 2

Answer:

greatest - 99935

smallest - 10005

Step-by-step explanation:

I hope you like answer