Question

find the greatest and the least number of five digits which are divisible by 26 , 39 and 28

please answer fast and give certified answer only other wise I will report....​

Answer 1

Answer:

Greatest number 99372, Least number 10920

Step-by-step explanation:

LCM of 26, 39, 28 is

26=2×13

39=3×13

28=2×2×7

LCM=2×2×3×7×13=1092

Now, the smallest 5 digit number is 10000 which when dividing by 1092, gives us a quotient of 9 plus some remainder.

Hence we shall multiply 1092 by the next integer 10 to get 10920 as the least 5 digit number divisible by 26, 39, 28

Again, the greatest 5 digit number is 99999 which when divided by 1092, gives us a quotient of 91 plus some remainder.

Hence we shall multiply 1092 by this integer 91, to get 99372 as the greatest 5 digit number divisible by 26, 39, 28.