Question

find the greatest consecutive or integers whose sum is at most 125​

Answer 1

Answer:

Sum of five consecutive odd intrgers is 125.

Let first one be x.

Then, Second Number = x+2

Third Number = x+4

Fourth Number= x+6, and

Fifth Number= x+8

ATQ,

x + (x+2) + (x+4) + (x+6) + (x+8) = 125

5x + 20 = 125

5x = 105

x = 21

Therefore, other consecutive integers = 23, 25, 27 and 29.

Now, the sum of the second largest number and the product of the largest number and smallest number.

Second Largest Number= 27

Largest Number = 29, and

Smallest Number= 21

So,

27 + (29×21)

= 27 + 609

= 616

Hope It Helps