Find the greatest five digit number exactly divisible by 32, 60, 96 and 100
Answers
What is the greatest 5 digit number which is exactly divisible by 8, 15, and 21?
it is solve by this method only.....
try to understand it....
8 factors as 2*2*2
15 factors as 3*5
21 factors as 3*7
So, all numbers divisible by all three MUST be multiples of 2*2*2*3*5*7=840
The largest five digit number is 99999
Dividing that by 840 is 119 and a small remainder
840 times 119 is 99960
Which is therefore the largest five digit number divisible by 8, by 15, and by 21.
However, if you need a number divisible by all three, one after the other, then this number must instead be a multiple of 8*15*21=2520
2520 goes into 99999 39 times and change
39 times 2520 is 98280, so if that’s what your question meant to ask, that’s the answer, not quite as large as the largest five digit number each of the set can be divided evenly into.
hope it helps you....
Answer:
96000
32×3000
96×1000
60×1600
100×960