Question

find the greatest five digit number which when divided by 12,24,30,36 and 45 leaves remainder 8 in each case?​

Answer 1

Answer:

The difference between the divisor and the remainder is same in all the cases which is 6

STEP 1:

LCM OF DIVISORS

LCM OF( 9,12,24,45) IS 360

STEP 2:

We know the largest five digit number is 99999

Now to find the largest five digit number which satisfy the given conditons then do the following

A) 360*N-6

N, is the quotient of 99999/360

you will get the answer as 360*277–6= 97214

B) Divide 99999/360

you will get remainder as 279

SUBTRACT 279 FROM 99999 WHICH IS 99720

Now 99720–6= 97214 which will be your answer.

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