find the greatest four digit number which is exactly divisible by 8,12 and 20
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first we will find lcm of 8,12 ansmd 20
8=2×2×2
12÷2×2×3
20=2×2×2
lcm =2×2×2×3×5=120
greatest 4 digit number is 9999 then divide this number by lcm of 8,12 and 2o 9999/120 will get remainder 39
now subtract 39 from the 4 digit number 9999-39=9960
996p is the greatest number 4 digit numver divisibel by 8,12 & 2o
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