Question

Find the greatest four-digit number which
leaves
remainder when divided by 15, 21 and
28.​

Answer 1

Step-by-step explanation:

the greatest four digit number = 9999

ATOQ

9999/ 15= quotient: 666

remainder = 09

so the greatest 4 digit number divisible by 15 is 9999 - 9 = 9990 ans

the greatest four digit number = 9999

9999/ 2 = quotient : 476

remainder : 03

so the greatest four digit number divisible by 21 is 9999 - 03 = 9996

I HOPE IT WILL HELP YOU