Question

find the greatest greatest number which divides which divides 121, 226 and 259 and leaves remainder 1, 2 and 3 respectively​

Answer 1

Answer:

8 is the  largest number that divides 121, 226 and 259 and leaves remainder of 1,2 and 3 respectively.

Step-by-step explanation:

Subtract the given remainders from the numbers that are given :-

121 - 1 = 120 = 2 x 2 x 2 x 3 x 5 = 2^3 x 3 x 5

226 - 2 = 224 = 2 x 2 x 2 x 2 x 2 x 7 =2^5 x 7

259 - 3 = 256 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 2^8

Common prime factors: 2

Common prime factors with the lowest exponent: 2^3

HCF (120, 224, 256 ) = 8

∴  8 is the  largest number that divides 121, 226 and 259 and leaves remainder of 1,2 and 3 respectively.

Answer 2

8 is the answer of this question