Math, asked by Goonj1947, 10 months ago

Find the greatest no. less than 900 which is divisible by 8,12 and 28. pls answer fast​

Answers

Answered by beenishsuri909
1

Answer:

Step-by-step explanation:

The least number divisible by 8 ,12 and 28 is 84. Multiple of 84 will be exactly divisible by each of the numbers 8 , 12 and 28. Since the required number is not exceed 900, required number = 84* 10 =840

Answered by hariomsanjeev
1

Answer: It will be the product of  LCM and HCF of 8, 12 and 28 and that is

168*4= 672.

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