Question

Find the greatest no. of 4 digit which when divided by 10,11,15 and 22 leaves 3,4,8 and 15 as remainder resptively

Answer 1

Answer: 9893

Step-by-step explanation:

Let m be the required number

Here 10-3=11-4=15-8=22-15=7

Then m+7 will be a multiple of the LCM OF 10, 11, 15 and 22

10=2x5

11=1x11

15=3x5

22=2x11

So LCM=2x5x11x3=330

Greatest 4 digit number is 9999 which when divided by 330 leaves a remainder 99

So the greatest 4 digit number divisible by 330 is 9999-99=9900

So m+7=9900

m=9893