find the greatest no. of 5 digit exactly divisible by 12 , 15 and 36.
please do it in a paper .....plz
HiteshSinghgi:
hey
Answers
Answered by
3
Hey there!
First we will find the LCM of 12,15 and 36
By prime Factorisation,
12=2*2*3
15=5*3
36=2*2*3*3
Now, LCM= 22*32*5
We will find that the LCM is 180
Now, Largest 5 digit number= 99999
Dividing this number by LCM, we get,
99999/180=555.5
Now we will multiply 180 by 555
We will get 99900
We will check now and observe,
99900/12=8325
99900/15=6660
99900/36=2775
Hence 99900 is the greatest 5 digit number divisible by 12,15 and 36.
Hope it helped!☺️
First we will find the LCM of 12,15 and 36
By prime Factorisation,
12=2*2*3
15=5*3
36=2*2*3*3
Now, LCM= 22*32*5
We will find that the LCM is 180
Now, Largest 5 digit number= 99999
Dividing this number by LCM, we get,
99999/180=555.5
Now we will multiply 180 by 555
We will get 99900
We will check now and observe,
99900/12=8325
99900/15=6660
99900/36=2775
Hence 99900 is the greatest 5 digit number divisible by 12,15 and 36.
Hope it helped!☺️
Answered by
1
The answer is 99900.
Method
For the number to be exactly divisible by all the three numbers i.e 15,12 and 25 , we have to take their LCM.
LCM=300.
Now it is asked that number should be greatest 5 digit number. So, in order to find out the such number, divide 99999 by 300. The quotient ×300 (333×300) is the answer which would be largest 5 digit number.
Method
For the number to be exactly divisible by all the three numbers i.e 15,12 and 25 , we have to take their LCM.
LCM=300.
Now it is asked that number should be greatest 5 digit number. So, in order to find out the such number, divide 99999 by 300. The quotient ×300 (333×300) is the answer which would be largest 5 digit number.
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