Find the greatest no. Of 6 digit exactly divisible by 24, 15, 36
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Answered by
429
Given integers,
24 , 15 and 36
Prime factorization of,
24=2³×3
15=3×5
36=2²×3²
LCM=product of each prime factor of highest power
LCM=2³×3²×5=360
Greatest six digit number=999999
Greatest six digit number exactly divisible by given numbers=999999-remainder when 999999 is divided by LCM of given numbers
Greatest six digit number exactly divisible by given numbers=999999-279=999720
Hence greatest six digit number exactly divisible by 24 , 15 and 36 is 999720
24 , 15 and 36
Prime factorization of,
24=2³×3
15=3×5
36=2²×3²
LCM=product of each prime factor of highest power
LCM=2³×3²×5=360
Greatest six digit number=999999
Greatest six digit number exactly divisible by given numbers=999999-remainder when 999999 is divided by LCM of given numbers
Greatest six digit number exactly divisible by given numbers=999999-279=999720
Hence greatest six digit number exactly divisible by 24 , 15 and 36 is 999720
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161
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