Find the greatest no. of six digit exactly divisible by 24,15and36?
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Hey friend
Firstly find the LCM of given number.
LCM of (24,15,36) is 360.
The greatest 6-digit number=999999.
After that , divide 999999 by 360.
And substract the remainder from 999999.
→999999/360
Quotient=277
Remainder=279.
999999-279=999720.
Hence,999720 is the answer.
Hope it's helpful for you:(☺☺☺✌✌✌.
Firstly find the LCM of given number.
LCM of (24,15,36) is 360.
The greatest 6-digit number=999999.
After that , divide 999999 by 360.
And substract the remainder from 999999.
→999999/360
Quotient=277
Remainder=279.
999999-279=999720.
Hence,999720 is the answer.
Hope it's helpful for you:(☺☺☺✌✌✌.
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hey ananya ! i have this question a little different which is " find the greatest number of hcf of six digits exactly divisible by 24,15 and 36
idk which one's correct
and can anybody explain that in this question it's given find 'greatest no.' than why did we find LCM ; why not HCF
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Secondary School Math 8+4 pts
Find the greatest no. of six digit exactly divisible by 24,15and36?
Report by Ananya01062003 22.05.2018
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hebbarrajeev
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SachinKrMb
SachinKrMbMaths AryaBhatta
Hey friend
Firstly find the LCM of given number.
LCM of (24,15,36) is 360.
The greatest 6-digit number=999999.
After that , divide 999999 by 360.
And substract the remainder from 999999.
999999/360
Quotient=277
Remainder=279.
999999-279=999720.
Hence,999720 is the answer.
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