Question

Find the greatest no that will divide 445 ,572 & 699 leaving remainder 4 ,5 & 6

Answer 1

since we need a HCF of a no. be x so while dividing the remainder must be 4,5,6 respectively so minus value so we will get 441 , 567 , 693

now taking hcf

441= 3x3x7x7

567=3x3x3x3x7

693=3x3x7x11

hcf= 3x3x7 = 63 is the required no. ie (x)