find the greatest no. that will divide 445 ,572 and 699 leaving remainders
4 , 5 and 6 respectively.
Answers
Answered by
13
good question-
first we will subtract-
445-4, 572-5, 699-6
then we will find hcf friend-
441 = 3 x 3 x 7 x 7
572 = 3 x 3 x 3 x 3 x 7
693 = 3 x 3 x 7 x 11
so,hcf is 63 friend.
so friend now divide them-
441/63=7 and if we take real number then answer is 7 and remainder is 4.
572/63=9 and if we take real number then answer is 9 and remainder is 5.
693/63=11 and if we take real number then answer is 11 and remainder is 6.
please mark it brainliest.
first we will subtract-
445-4, 572-5, 699-6
then we will find hcf friend-
441 = 3 x 3 x 7 x 7
572 = 3 x 3 x 3 x 3 x 7
693 = 3 x 3 x 7 x 11
so,hcf is 63 friend.
so friend now divide them-
441/63=7 and if we take real number then answer is 7 and remainder is 4.
572/63=9 and if we take real number then answer is 9 and remainder is 5.
693/63=11 and if we take real number then answer is 11 and remainder is 6.
please mark it brainliest.
adityagupta190:
Thank you so much Pulkit! definitely i will mark this as the brainliest.
thanks please mark it brainliest.
pulkit i am not getting the tab to smash on for making your answer as brainliest
wait
ask the question 2) some will answer it 3) above every answer it is written that "mark as brainliest" 4) whose answer u like the most mark ...
these are steps.
Similar questions