Question

find the greatest no. that will divide 455 , 582 and 710 leaving remainders 14 , 15, 17​

Answer 1

Answer:

Given numbers are 455, 582 and 710 and the respective remainders are 14, 15 and 17.

We have 455 – 14 = 441, 582 – 15 = 567 and 710 – 17 = 693.

Now let us find their HCF.

Playing With Numbers Class 6 Extra Questions Maths Chapter 3  

Common factors are 3 and 7.

∴ HCF = 3 x 7 = 21

Hence, the required number is 21.

Answer 2

Answer:

find the greatest no. that will divide 455 , 582 and 710 leaving remainders 14 , 15, 17