Question

Find the greatest no
which devided 2300 and 3500
leaving 32 and 56, respectively.
as remainders.​

Answer 1

to solve this first of all we have to

subtract 32 and 56 from 2300 and 3500

$2300 - 32 = 2268$

$3500 - 56 = 3444$

so the required greatest number will be equal to hcf of 2268 and 3444

I'm doing this by prime factorisation method

hcf is 84

so the required number is 84 .

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