Question

Find the greatest no. which will divide 410,751 and 1030 so as to leave remainder 7 in each case

Answer 1

Firstly subtract 7 from both numbers and then find their HCF.
Yhe HCF will be the greatest number.

Answer 2

$to \: find \: that \: number \: first \: of \: all \\ \: subtract \: 7 \: from \: 410751 \: and \: 1030.$
$new \: numbers \: are \: 410744 \: and \: 1023.$
Now take there HCF.

see in attached file.

HCF = 1