Math, asked by Khushioberoijb9517, 7 months ago

Find the greatest num that divides 396 exactly but divides 619 to give remainder 7

Answers

Answered by sathyamargerate0410
0

Step-by-step explanation:

Let the number be n

Case 1:

divisor=396

Dividend=n

Quotient=q

Remainder=0

Dividend=(Divisor×Quotient)+Remainder

n=396q

Case2:

divisor=619

Remainder=7

Quotient=q,

Dividend=n

Dividend=(Divisor×Quotient)+Remainder

n=619q,+7

619q,=n-7

619q,=396q-7

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