Math, asked by janasaurabh1993, 5 months ago

Find the greatest number by which must
2300 and 3500 be divided to leave the
remainders 32 and 56 respectively.​

Answers

Answered by suryansh20032001
1

Answer:

2300-32 = 2268

3500-56 = 3444

Take the HCF of 2268 and 3444

2268 = 2 * 2 * 3 * 3 * 3 * 3 * 7.

3444 = 2 * 2 * 3 * 7 * 41

Step-by-step explanation:

hope it helps:-)

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