find the greatest number number of 3 digits which when dividend by 20,24 and 45 leave a remainder 9 in each case.
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The LCM of 20, 24 and 45 is 360.
The greatest 3-digit number = 999
Divide 999by360. The remainder is 279.
The greatest 3-digit number divisible by 360 is 999-279=720.
Therefore, the greatest 3-digit number divisible by 360 and leaving a remainder 9 is 720+9=729.
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