Find the greatest number of 3-digit exactly divisible by 8, 10 and 12.
Answers
Answer:
960
Step-by-step explanation:
Let us calculate the L.C.M 8, 10 and 12
L.C.M of 8, 10, 12 = 2 x 2 x 2 x 3 x 5
LCM of 8, 10, 12 = 120
We have to find the greatest 3 digit multiple of 120
∴ the number is
120 x 8 = 960
120 x 10 = 1200
120 x 12 = 1440
The 1200 and 1440 are not 3-digit numbers.
Hence, the greatest 3- digit number exactly divisible by 8, 10 & 12 is 960.
Now, let us check whether 960 is divisible by 8, 10 and 12.
960 ÷ 8 = 120
960 ÷ 10 = 96
960 ÷ 12 = 80
So the greatest 3-digit number is 960.
Step-by-step explanation:
Let us calculate the L.C.M 8, 10 and 12
L.C.M of 8, 10, 12 = 2 x 2 x 2 x 3 x 5
LCM of 8, 10, 12 = 120
We have to find the greatest 3 digit multiple of 120
∴ the number is
120 x 8 = 960
120 x 10 = 1200
120 x 12 = 1440
The 1200 and 1440 are not 3-digit numbers.
Hence, the greatest 3- digit number exactly divisible by 8, 10 & 12 is 960.
Now, let us check whether 960 is divisible by 8, 10 and 12.
960 ÷ 8 = 120
960 ÷ 10 = 96
960 ÷ 12 = 80
So the greatest 3-digit number is 960.