find the greatest number of 4 digit which is exactly divisible by 15 24 and 36.
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anish106:
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15 = 3 × 5
24 = 2 × 2 × 2 × 3
36 = 2 × 2 × 3 × 3
LCM = 3 × 3 × 5 × 2 × 2 × 2 => 45×8=360
Multiply the LCM by 3
360×3
Hence, 1080 is the least required number.
To know the Largest required number =>
9999÷360
Remainder = 279
Hence, required number is 9999-279 = 9720
I hope this will help you
(-:
24 = 2 × 2 × 2 × 3
36 = 2 × 2 × 3 × 3
LCM = 3 × 3 × 5 × 2 × 2 × 2 => 45×8=360
Multiply the LCM by 3
360×3
Hence, 1080 is the least required number.
To know the Largest required number =>
9999÷360
Remainder = 279
Hence, required number is 9999-279 = 9720
I hope this will help you
(-:
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