Question

find the greatest number of 4 digit which is excatly divisible by 30 36 and 60​

Answer 1

Answer:

$The required number is 9996 which is exactly divisible by 40, 48 and 60.</p><p></p><p>Step-by-step explanation:</p><p></p><p>To find : The Greatest 4-digit number exactly divisible by 40, 48 and 60?</p><p></p><p>Solution :  </p><p></p><p>The greatest 4-digit number is 9999.</p><p></p><p>Now, Find the LCM of 40, 48 and 60.</p><p></p><p>40=2\times 2\times 540=2×2×5</p><p></p><p>48=2\times 2\times2\times 2\times 348=2×2×2×2×3</p><p></p><p>60=2\times 2\times 3\times 560=2×2×3×5</p><p></p><p>LCM(40,48,60)=2\times 2LCM(40,48,60)=2×2</p><p></p><p>LCM(40,48,60)=4LCM(40,48,60)=4</p><p></p><p>Divide 9999 by 4 so that we get the remainder,</p><p></p><p>9999 = 2499\times4 + 39999=2499×4+3</p><p></p><p>Remainder is 3.</p><p></p><p>Now, Subtract the remainder from 9999.</p><p></p><p>9999-3=99969999−3=9996</p><p></p><p>Therefore, The required number is 9996 which is exactly divisible by 40, 48 and 60.</p><p></p><p>$

I hope both answer r helpful to u

Answer 2

Step-by-step explanation:

here LCM is 180 of these no. 30,36 and 60

greatest number of 4 digit is = 9999

=> 9999÷180

here it's remainder is 99

=>9999-99

=>9900

greatest number of 4 digit which is divisible by 30,36 ,60