Question

Find the greatest number of 4 digits and the least number of 5 digits that have as their H.C.F. 147
A) 9996 and 10, 143
B) 9936 and 10,080
C) 9996 and 10,080
D) 9936 and 10,140

Answer 1

A, 9996 and 10143 are the numbers.

prime factors of 9996=2×2×3×7×7×17

prime factors of 10143=3×3×7×7×23

where common factors are 3×7×7=147 (HCF)

Answer 2

Answer:

9996 and 10143

Step-by-step explanation:

Let us take the greatest four digit number 9999

If we divide it by 147 we will get remainder as 3

So, subtract 3 from 9999

We will get 9996

And we can represent 9996= 147 * x

We will find that x is 68

So 68+1 will give the least five digit number

147*69 gives the other number 10143

So answer is 9996 & 10143