- Find the greatest number of 4-digits exactly
divisible by 12, 16, 24, 28 and 36. full explain .
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Therefore the greatest 4 digit number exactly divisible by 12 16 24 28 and 36 is the product 144*69.so, dividing by 9999 by 1008 we get 9 as quotient and 927 as remainder. 9999-927=9072.
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Answer:
9999-927=9072 is the correct answer
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